Sự cố tự tham gia

Question

Tôi có bảng có tên là tblAccInfo, bên dưới là dữ liệu bảng. Tôi cần đầu ra như dưới đây.

Input 
PolicyNumber BankAc StorageDate VerNum 
400  123  2012-01-01  1 
400  164  2012-01-03  2 
400  860  2012-01-05  3 
6004317654  301  2012-02-05  1 
6004317654  615  2012-03-01  2 
6004317654  253  2012-03-12  3 
6004317654  887  2012-04-03  4 

OUTPUT

PolicyNumber IntialBankAc IntialSDate VerNum LatestBankAc LatestSDate VerNum 
400 123   2012-01-01 1  860   2012-01-05 3 
6004317654 301   2012-02-05 1  887   2012-04-03 4 

Tôi đã thử với bên dưới tự tham gia, nhưng không thành công. Xin hãy giúp tôi trong việc này.

Select DISTINCT 
    P.PolicyNumber, 
    P.BankAc [IntialBankAc], 
    P.StorageDate IntialSDate], 
    P.VerNum, 
    P1.BankAc [LatestBankAc], 
    P1.StorageDate [LatestSDate], 
    P1.VerNum 
FROM tblAccInfo P 
INNER JOIN tblAccInfo P1 
ON P1.PolicyNumber=P.PolicyNumber 
AND (P.BankAc<>P1.BankAc AND P.StorageDate<>P1.StorageDate AND P.VerNum<>P1.VerNum) 

Answer 1

Hãy thử điều này:

SELECT 
    T1.PolicyNumber, 
    T2.BankAc AS IntialBankAc, 
    T2.StorageDate AS IntialSDate, 
    T2.VerNum AS InitalVerNum, 
    T3.BankAc AS LatestBankAc, 
    T3.StorageDate AS LatestSDate, 
    T3.Vernum AS LatestVerNum 
FROM 
(
    SELECT 
     PolicyNumber, 
     MIN(VerNum) AS MinVerNum, 
     MAX(VerNum) AS MaxVerNum 
    FROM tblAccInfo 
    GROUP BY PolicyNumber 
) AS T1 
JOIN tblAccInfo AS T2 
ON T1.PolicyNumber = T2.PolicyNumber 
AND T1.MinVerNum = T2.VerNum 
JOIN tblAccInfo AS T3 
ON T1.PolicyNumber = T3.PolicyNumber 
AND T1.MaxVerNum = T3.VerNum 

Xem nó làm việc trực tuyến: sqlfiddle

Answer 2

chưa được kiểm tra - nhưng sẽ cung cấp cho bạn ý tưởng. (. Có thể có một cách hiệu quả hơn để làm điều này - đó chỉ là phương pháp mà nhảy ra khỏi tôi)

select initial.policynumber 
,initial.initialbankaccoutn 
,initial.initialstoragedate 
,initial.intialvernum 
,final.latestbankaccount 
,final.lateststoragedate 
,final.latestvernum 
from 
(select a.policynumber, a.bankaccount as initialbankaccount, a.storagedate as initialstoragedate, a.vernum as initialvernum 
from tblAccInfo a1 
    inner join (select min(storagedate) as storagedate, policynumber 
       from tblAccInfo 
       group by policynumber) a 
       on a.policynumber = a1.policynumber 
       and a.storagedate = a1.storagedate) initial 
inner join 
(select b.policynumber, b.bankaccount as latestbankaccount, b.storagedate as lateststoragedate, b.vernum as latestvernum 
from tblAccInfo b1 
    inner join (select min(storagedate) as storagedate, policynumber 
       from tblAccInfo 
       group by policynumber) b 
       on a.policynumber = b1.policynumber 
       and a.storagedate = b1.storagedate) final 
on final.policynumber = initial.policynumber 

Answer 3

DECLARE @x TABLE 
(
    PolicyNumber VARCHAR(32), 
    BankAc  INT, 
    StorageDate DATE, 
    VerNum  INT 
); 

INSERT @x VALUES 
('400','123','2012-01-01',1), 
('400','164','2012-01-03',2), 
('400','860','2012-01-05',3), 
('6004317654','301','2012-02-05',1), 
('6004317654','615','2012-03-01',2), 
('6004317654','253','2012-03-12',3), 
('6004317654','887','2012-04-03',4); 

WITH x AS 
(
    SELECT PolicyNumber, BankAc, StorageDate, VerNum, 
     f = ROW_NUMBER() OVER (PARTITION BY PolicyNumber ORDER BY VerNum), 
     l = ROW_NUMBER() OVER (PARTITION BY PolicyNumber ORDER BY VerNum DESC) 
    FROM @x 
) 
SELECT 
    x.PolicyNumber, 
    InitialBankAc = x.BankAc, 
    InitialSDate = x.StorageDate, 
    InitialVerNum = x.VerNum, 
    LatestBankAc = x2.BankAc, 
    LatestSDate  = x2.StorageDate, 
    LatestVerNum = x2.VerNum 
FROM x INNER JOIN x AS x2 
ON x.PolicyNumber = x2.PolicyNumber 
WHERE x.f = 1 AND x2.l = 1 
ORDER BY x.PolicyNumber;