tôi có thể tạo chương trình này:
import pygame, sys, time, random, easygui
skier_images = ["skier_down.png", "skier_right1.png",
"skier_right2.png", "skier_left2.png",
"skier_left1.png"]
class SkierClass(pygame.sprite.Sprite):
def __init__(self):
pygame.sprite.Sprite.__init__(self)
self.image = pygame.image.load("skier_down.png")
self.rect = self.image.get_rect()
self.rect.center = [320, 100]
self.angle = 0
def turn(self, direction):
self.angle = self.angle + direction
if self.angle < -2: self.angle = -2
if self.angle > 2: self.angle = 2
center = self.rect.center
self.image = pygame.image.load(skier_images[self.angle])
self.rect = self.image.get_rect()
self.rect.center = center
speed = [self.angle, 6 - abs(self.angle) * 2]
return speed
def move(self,speed):
self.rect.centerx = self.rect.centerx + speed[0]
if self.rect.centerx < 20: self.rect.centerx = 20
if self.rect.centerx > 620: self.rect.centerx = 620
class ObstacleClass(pygame.sprite.Sprite):
def __init__(self,image_file, location, type):
pygame.sprite.Sprite.__init__(self)
self.image_file = image_file
self.image = pygame.image.load(image_file)
self.location = location
self.rect = self.image.get_rect()
self.rect.center = location
self.type = type
self.passed = False
def scroll(self, t_ptr):
self.rect.centery = self.location[1] - t_ptr
def create_map(start, end):
obstacles = pygame.sprite.Group()
gates = pygame.sprite.Group()
locations = []
for i in range(10):
row = random.randint(start, end)
col = random.randint(0, 9)
location = [col * 64 + 20, row * 64 + 20]
if not (location in locations) :
locations.append(location)
type = random.choice(["tree", "flag"])
if type == "tree": img = "skier_tree.png"
elif type == "flag": img = "skier_flag.png"
obstacle = ObstacleClass(img, location, type)
obstacles.add(obstacle)
return obstacles
def animate():
screen.fill([255,255,255])
pygame.display.update(obstacles.draw(screen))
screen.blit(skier.image, skier.rect)
screen.blit(score_text, [10,10])
pygame.display.flip()
def updateObstacleGroup(map0, map1):
obstacles = pygame.sprite.Group()
for ob in map0: obstacles.add(ob)
for ob in map1: obstacles.add(ob)
return obstacles
pygame.init()
screen = pygame.display.set_mode([640,640])
clock = pygame.time.Clock()
skier = SkierClass()
speed = [0, 6]
map_position = 0
points = 0
map0 = create_map(20, 29)
map1 = create_map(10, 19)
activeMap = 0
obstacles = updateObstacleGroup(map0, map1)
font = pygame.font.Font(None, 50)
a = True
while a:
clock.tick(30)
for event in pygame.event.get():
if event.type == pygame.QUIT: sys.exit()
if event.type == pygame.KEYDOWN:
if event.key == pygame.K_LEFT:
speed = skier.turn(-1)
elif event.key == pygame.K_RIGHT:
speed = skier.turn(1)
skier.move(speed)
map_position += speed[1]
if map_position >= 640 and activeMap == 0:
activeMap = 1
map0 = create_map(20, 29)
obstacles = updateObstacleGroup(map0, map1)
if map_position >=1280 and activeMap == 1:
activeMap = 0
for ob in map0:
ob.location[1] = ob.location[1] - 1280
map_position = map_position - 1280
map1 = create_map(10, 19)
obstacles = updateObstacleGroup(map0, map1)
for obstacle in obstacles:
obstacle.scroll(map_position)
hit = pygame.sprite.spritecollide(skier, obstacles, False)
if hit:
if hit[0].type == "tree" and not hit[0].passed:
skier.image = pygame.image.load("skier_crash.png")
easygui.msgbox(msg="OOPS!!!")
choice = easygui.buttonbox("Do you want to play again?", "Play", ("Yes", "No"))
if choice == "Yes":
skier = SkierClass()
speed = [0, 6]
map_position = 0
points = 0
map0 = create_map(20, 29)
map1 = create_map(10, 19)
activeMap = 0
obstacles = updateObstacleGroup(map0, map1)
elif choice == "No":
a = False
quit()
elif hit[0].type == "flag" and not hit[0].passed:
points += 10
obstacles.remove(hit[0])
score_text = font.render("Score: " + str(points), 1, (0, 0, 0))
animate()
Link: https://docs.google.com/document/d/1U8JhesA6zFE5cG1Ia3OsTL6dseq0Vwv_vuIr3kqJm4c/edit
Ok, Ok. Đủ công bằng. Bạn không * cần * 2 'while' vòng - Nhưng tôi vẫn nghĩ rằng nó sạch hơn theo cách đó :) - Tôi thực sự thích giải pháp trang trí của tôi, nhưng đó có thể là một chút tiên tiến cho một câu hỏi như thế này ... – mgilson
@ mgilson - Có thể. Nhưng trang trí * chắc chắn là * khá gọn gàng, +1. – root