có giới hạn đối với những gì sql fiddle có thể xử lý không? sql fiddle không biên dịch bất cứ điều gì và trả về không có thông báo lỗi

Question

Gần đây tôi đã tạo một truy vấn để biên dịch thành công và trả về kết quả mong muốn. Khi tôi sử dụng đoạn mã đó như một truy vấn phụ trong một đoạn mã khác mà người dùng trên stackoverflow đã đưa ra cho tôi, tôi đã gặp phải một vài vấn đề, cuối cùng đã được giải quyết. Tôi đã cố gắng sử dụng truy vấn này dưới dạng truy vấn phụ trong đoạn mã được cung cấp cho tôi. Tuy nhiên, sql fiddle không trả lại bất cứ điều gì. Không có lỗi hoặc thông báo được soạn thảo. Khi tôi cố gắng đưa vào một lỗi cú pháp về mục đích giống như một dấu hiệu ngẫu nhiên +, không có gì xảy ra. có phải vì truy vấn quá dài không?

schema

CREATE TABLE sampleData 
    (
    id MEDIUMINT NOT NULL AUTO_INCREMENT, 
     timecode int, 
    count int, 
     PRIMARY KEY (id) 
    ) 
#ENGINE=MyISAM 
; 

INSERT INTO sampleData 
(timecode, count) 
VALUES 
(1344893440, 1), (1346014720, 1),(1344898688,1),(1345654784,1),(1345978368,1), 
(1345959296,1), (1345064704,1), (1345156352,1),(1345225600,1), 
(1345017984,1),(1345640960,1),(1346019968,1),(1345834752,1), 
(1345438464,1),(1344986880,1),(1345045632,1),(1345557888,1),(1344973056,1),(1345087232,1),(1345433216,1),(1345691008,1), 
(1344917760,1),(1345253248,1),(1344934912,1),(1345890048,1),(1345272448,1), (1345829504,1),(1345798400,1),(1345203200,1),(1344741120,1), 
(1345175552,1),(1344824192,1),(1344926336,1),(1345571712,1),(1344931584,1),(1345211776,1),(1345059456,1),(1345516288,1),(1345441920,1),(1346009472,1) 

truy vấn

select t_0.*, 
      (coalesce(t_3.average_number_of_votes_per_previous_period_days, 0) - coalesce(t_4.average_number_of_votes_per_previous_period_days, 0)) * 100.0 
    from 
     (select t.*, 
      (coalesce(t_1.count, 0) - coalesce(t_2.count, 0)) * 100.0 as "percentage increase in count in %" 
    from 
    (
     SELECT sum(1) AS ordr, 
     t1.id,t1.day, t1.count, SUM(t2.count) as aggregate, (SUM(t2.count)-t1.count)/(sum(1)-1) as "average_number_of_votes_per_previous_period_days" 

     FROM 
     (SELECT id, date(FROM_UNIXTIME(timecode)) AS day,(FROM_UNIXTIME(timecode)) AS original, COUNT(1) as 'count' 
     FROM sampleData 
     GROUP BY DAY) t1 
     INNER JOIN 
     (SELECT date(FROM_UNIXTIME(timecode)) AS day,(FROM_UNIXTIME(timecode)) AS original, COUNT(1) as 'count' 
     FROM sampleData 
     GROUP BY DAY) t2 
     on t1.day >= t2.day                                 
     GROUP BY t1.day, t1.count 
     ORDER BY t1.day 
     )t 
     left outer join 
     (
      SELECT sum(1) AS ordr, 
      t1.id,t1.day, t1.count, SUM(t2.count) as aggregate, (SUM(t2.count)-t1.count)/(sum(1)-1) as "average_number_of_votes_per_previous_period_days" 
      FROM 
      (SELECT id, date(FROM_UNIXTIME(timecode)) AS day,(FROM_UNIXTIME(timecode)) AS original, COUNT(1) as 'count' 
      FROM sampleData 
      GROUP BY DAY) t1 
      INNER JOIN 
      (SELECT date(FROM_UNIXTIME(timecode)) AS day,(FROM_UNIXTIME(timecode)) AS original, COUNT(1) as 'count' 
      FROM sampleData 
      GROUP BY DAY) t2 
      on t1.day >= t2.day                                 
      GROUP BY t1.day, t1.count 
      ORDER BY t1.day 
     )t_1 
     on t.ordr = t_1.ordr + 1 left outer join 
     (
      SELECT sum(1) AS ordr, 
      t1.id,t1.day, t1.count, SUM(t2.count) as aggregate, (SUM(t2.count)-t1.count)/(sum(1)-1) as "average_number_of_votes_per_previous_period_days" 
      FROM 
       (SELECT id, date(FROM_UNIXTIME(timecode)) AS day,(FROM_UNIXTIME(timecode)) AS original, COUNT(1) as 'count' 
       FROM sampleData 
       GROUP BY DAY) t1 
      INNER JOIN 
       (SELECT date(FROM_UNIXTIME(timecode)) AS day,(FROM_UNIXTIME(timecode)) AS original, COUNT(1) as 'count' 
       FROM sampleData 
       GROUP BY DAY) t2 
      on t1.day >= t2.day                                 
      GROUP BY t1.day, t1.count 
      ORDER BY t1.day 
      ) t_2 
     on t.ordr = t_2.ordr + 2)t_0 
    left outer join 
     (select t.*, 
      (coalesce(t_1.count, 0) - coalesce(t_2.count, 0)) * 100.0 as "percentage increase in count in %" 
    from 
    (
     SELECT sum(1) AS ordr, 
     t1.id,t1.day, t1.count, SUM(t2.count) as aggregate, (SUM(t2.count)-t1.count)/(sum(1)-1) as "average_number_of_votes_per_previous_period_days" 

     FROM 
     (SELECT id, date(FROM_UNIXTIME(timecode)) AS day,(FROM_UNIXTIME(timecode)) AS original, COUNT(1) as 'count' 
     FROM sampleData 
     GROUP BY DAY) t1 
     INNER JOIN 
     (SELECT date(FROM_UNIXTIME(timecode)) AS day,(FROM_UNIXTIME(timecode)) AS original, COUNT(1) as 'count' 
     FROM sampleData 
     GROUP BY DAY) t2 
     on t1.day >= t2.day                                 
     GROUP BY t1.day, t1.count 
     ORDER BY t1.day 
     )t 
     left outer join 
     (
      SELECT sum(1) AS ordr, 
      t1.id,t1.day, t1.count, SUM(t2.count) as aggregate, (SUM(t2.count)-t1.count)/(sum(1)-1) as "average_number_of_votes_per_previous_period_days" 
      FROM 
      (SELECT id, date(FROM_UNIXTIME(timecode)) AS day,(FROM_UNIXTIME(timecode)) AS original, COUNT(1) as 'count' 
      FROM sampleData 
      GROUP BY DAY) t1 
      INNER JOIN 
      (SELECT date(FROM_UNIXTIME(timecode)) AS day,(FROM_UNIXTIME(timecode)) AS original, COUNT(1) as 'count' 
      FROM sampleData 
      GROUP BY DAY) t2 
      on t1.day >= t2.day                                 
      GROUP BY t1.day, t1.count 
      ORDER BY t1.day 
     )t_1 
     on t.ordr = t_1.ordr + 1 left outer join 
     (
      SELECT sum(1) AS ordr, 
      t1.id,t1.day, t1.count, SUM(t2.count) as aggregate, (SUM(t2.count)-t1.count)/(sum(1)-1) as "average_number_of_votes_per_previous_period_days" 
      FROM 
       (SELECT id, date(FROM_UNIXTIME(timecode)) AS day,(FROM_UNIXTIME(timecode)) AS original, COUNT(1) as 'count' 
       FROM sampleData 
       GROUP BY DAY) t1 
      INNER JOIN 
       (SELECT date(FROM_UNIXTIME(timecode)) AS day,(FROM_UNIXTIME(timecode)) AS original, COUNT(1) as 'count' 
       FROM sampleData 
       GROUP BY DAY) t2 
      on t1.day >= t2.day                                 
      GROUP BY t1.day, t1.count 
      ORDER BY t1.day 
      ) t_2 
     on t.ordr = t_2.ordr + 2) t_3 
     on t.ordr = t_3.ordr + 1 
    left outer join 
     (select t.*, 
      (coalesce(t_1.count, 0) - coalesce(t_2.count, 0)) * 100.0 as "percentage increase in count in %" 
    from 
    (
     SELECT sum(1) AS ordr, 
     t1.id,t1.day, t1.count, SUM(t2.count) as aggregate, (SUM(t2.count)-t1.count)/(sum(1)-1) as "average_number_of_votes_per_previous_period_days" 

     FROM 
     (SELECT id, date(FROM_UNIXTIME(timecode)) AS day,(FROM_UNIXTIME(timecode)) AS original, COUNT(1) as 'count' 
     FROM sampleData 
     GROUP BY DAY) t1 
     INNER JOIN 
     (SELECT date(FROM_UNIXTIME(timecode)) AS day,(FROM_UNIXTIME(timecode)) AS original, COUNT(1) as 'count' 
     FROM sampleData 
     GROUP BY DAY) t2 
     on t1.day >= t2.day                                 
     GROUP BY t1.day, t1.count 
     ORDER BY t1.day 
     )t 
     left outer join 
     (
      SELECT sum(1) AS ordr, 
      t1.id,t1.day, t1.count, SUM(t2.count) as aggregate, (SUM(t2.count)-t1.count)/(sum(1)-1) as "average_number_of_votes_per_previous_period_days" 
      FROM 
      (SELECT id, date(FROM_UNIXTIME(timecode)) AS day,(FROM_UNIXTIME(timecode)) AS original, COUNT(1) as 'count' 
      FROM sampleData 
      GROUP BY DAY) t1 
      INNER JOIN 
      (SELECT date(FROM_UNIXTIME(timecode)) AS day,(FROM_UNIXTIME(timecode)) AS original, COUNT(1) as 'count' 
      FROM sampleData 
      GROUP BY DAY) t2 
      on t1.day >= t2.day                                 
      GROUP BY t1.day, t1.count 
      ORDER BY t1.day 
     )t_1 
     on t.ordr = t_1.ordr + 1 left outer join 
     (
      SELECT sum(1) AS ordr, 
      t1.id,t1.day, t1.count, SUM(t2.count) as aggregate, (SUM(t2.count)-t1.count)/(sum(1)-1) as "average_number_of_votes_per_previous_period_days" 
      FROM 
       (SELECT id, date(FROM_UNIXTIME(timecode)) AS day,(FROM_UNIXTIME(timecode)) AS original, COUNT(1) as 'count' 
       FROM sampleData 
       GROUP BY DAY) t1 
      INNER JOIN 
       (SELECT date(FROM_UNIXTIME(timecode)) AS day,(FROM_UNIXTIME(timecode)) AS original, COUNT(1) as 'count' 
       FROM sampleData 
       GROUP BY DAY) t2 
      on t1.day >= t2.day                                 
      GROUP BY t1.day, t1.count 
      ORDER BY t1.day 
      ) t_2 
     on t.ordr = t_2.ordr + 2) t_4 
     on t_0.ordr = t_4.ordr + 2 

Answer 1

Tôi đã cắm truy vấn của bạn trong this fiddle, và bây giờ tôi thấy vấn đề. Truy vấn của bạn dài hơn 8000 ký tự (chính xác là 8423) và tôi không hiển thị thông báo đó trên bảng kết quả. Về cơ bản, đây là một lỗi hiển thị trong SQL Fiddle mà tôi đã không nhận thấy trước đó (vì vậy, cảm ơn vì đã chú ý đến điều này!).

Đồng thời, bạn có thể thử cắt bớt một số ký tự để làm cho nó vừa với giới hạn ký tự 8000.