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Tôi gặp vấn đề với tốc độ truy vấn trong Firebird. Sự chậm chạp trong phân loại và khác biệt.Truy vấn đơn đặt hàng chậm theo/phân biệt
Nếu tôi thử truy vấn trong MySQL thì anh ấy nhanh hơn một giây.
Firebird -> 1,3s một 1,6s MySQL -> 0,3s một 0,4s
Chúng tôi sử dụng cơ sở dữ liệu Firebird trên một máy chủ web/trang web, vì vậy tốc độ là quan trọng.
Thông số kỹ thuật: - Firebird 2.5.1 hoặc 2.5.2 (SuperClassic) 64 bit - 2,13 Ghz (2 bộ vi xử lý) - RAM 4,00 GB
tôi có thể làm gì?
tôi có các bảng sau:
==================================== ================
CREATE TABLE ARTICLE3_1
(
IDARTICLE Integer NOT NULL,
ITEMSTATUS Integer,
ITEMENTRYDATE Integer,
ITEMFILTER Integer,
ARTIKELNUMMER Varchar(250),
ARTIKELNAAM1 Varchar(250),
ARTIKELNAAM2 Varchar(250),
OMSCHRIJVING_DETAIL Blob sub_type 1,
OMSCHRIJVING1 Varchar(250),
OMSCHRIJVING2 Varchar(250),
ARTIKELNR_LEVERANCIER Varchar(250),
MERK Varchar(250),
LEVERANCIER Varchar(250),
EAN Varchar(250),
LINKAANGROEP Varchar(250),
LINKAANAANBIEDINGGROEP Varchar(250),
LINKAANPOPULAIRGROEP Varchar(250),
LINKAANART Varchar(250),
ARTGRPNR Varchar(250),
SUBGROEP Varchar(250),
PRIJSPER Integer,
VERKOOPPRIJS Float,
ADVIESPRIJS Float,
BTWPERC Float,
ONLINE Varchar(250),
TUSGROEPBIJLINK Varchar(250),
AFBEELDINGKLEIN Varchar(250),
AFBEELDINGMIDDEL Varchar(250),
AFBEELDINGGROOT Varchar(250),
ICECATLINK Varchar(250),
LINKAANHOMEPAGEGROEP Varchar(250),
LINKAANMIJNACCOUNTGROEP Varchar(250),
SORTEER Varchar(250),
AFBEELDING Varchar(100),
FLASH Blob sub_type 1,
EENHEID Varchar(250),
ALTARTNR1 Varchar(250),
ALTARTNR2 Varchar(250),
BESTELLENPER Float,
INFEED Varchar(250),
GOOGLE_TAXONOMIE Varchar(250),
FEED_TITEL Varchar(250),
FEED_OMSCHRIJVING Blob sub_type 1,
PRIMARY KEY (IDARTICLE)
);
CREATE INDEX IDX_ARTICLE3_1_2 ON ARTICLE3_1 (MERK);
CREATE INDEX IDX_ARTICLE3_1_3 ON ARTICLE3_1 (ARTIKELNUMMER);
CREATE INDEX IDX_ARTICLE3_1_4 ON ARTICLE3_1 (ARTIKELNR_LEVERANCIER);
CREATE INDEX IDX_ARTICLE3_1_5 ON ARTICLE3_1 (ALTARTNR2);
CREATE INDEX IDX_ARTICLE3_1_6 ON ARTICLE3_1 (ARTIKELNAAM1);
CREATE INDEX IDX_ARTICLE3_1_7 ON ARTICLE3_1 (EAN);
CREATE TABLE TREE3
(
IDLINK Integer NOT NULL,
LINKTYPE Integer,
IDITEM Integer,
ITEMTYPE Integer,
IDTARGETLINK Integer,
NODEPOSITION Integer,
NODELEVEL Integer,
IDLAYOUTDATA Integer,
IDTEMPLATE Integer,
ACTIONDATE Integer,
MARKET1 Integer,
PRIMARY KEY (IDLINK)
);
CREATE INDEX IDX_TREE3_2 ON TREE3 (IDITEM);
CREATE INDEX IDX_TREE3_3 ON TREE3 (MARKET1);
CREATE INDEX ITREE13 ON TREE3 (IDTARGETLINK,NODEPOSITION);
CREATE INDEX ITREE53 ON TREE3 (IDITEM,ITEMTYPE);
====================================================
Các truy vấn trong Firebird:
SELECT FIRST 30 SKIP 0 distinct tr.IdLink, tr.IdTargetLink, tr.IdItem, tr.NodePosition
FROM Tree3 tr
inner join article3_1 art on art.idarticle = Tr.iditem
WHERE tr.ItemType = 2 AND tr.Market1 = 1
AND ((art.IDARTICLE > 0) AND ( (LOWER(art.Artikelnummer) like '%a4 papier%') OR ((LOWER(art.Artikelnummer) like 'a4')
AND (LOWER(art.Artikelnummer) like 'papier')) OR (LOWER(art.Artikelnaam1) like '%a4 papier%') OR ((LOWER(art.Artikelnaam1) like '%a4%')
AND (LOWER(art.Artikelnaam1) like '%papier%')) OR (LOWER(art.Artikelnaam2) like '%a4 papier%') OR ((LOWER(art.Artikelnaam2) like '%a4%')
AND (LOWER(art.Artikelnaam2) like '%papier%')) OR (LOWER(art.Artikelnr_leverancier) like '%a4 papier%') OR ((LOWER(art.Artikelnr_leverancier) like '%a4%')
AND (LOWER(art.Artikelnr_leverancier) like '%papier%')) OR (LOWER(art.Merk) like '%a4 papier%') OR ((LOWER(art.Merk) like '%a4%')
AND (LOWER(art.Merk) like '%papier%')) OR (LOWER(art.EAN) like '%a4 papier%') OR ((LOWER(art.EAN) like '%a4%')
AND (LOWER(art.EAN) like '%papier%')) OR (LOWER(art.AltArtnr1) like '%a4 papier%') OR ((LOWER(art.AltArtnr1) like '%a4%')
AND (LOWER(art.AltArtnr1) like '%papier%')) OR (LOWER(art.AltArtnr2) like '%a4 papier%') OR ((LOWER(art.AltArtnr2) like '%a4%')
AND (LOWER(art.AltArtnr2) like '%papier%'))))
AND tr.NODELEVEL =5 and tr.LINKTYPE <> 5
ORDER BY tr.NodePosition
Các truy vấn trong MySQL:
SELECT distinct tr.IdLink, tr.IdTargetLink, tr.IdItem, tr.NodePosition
FROM Tree3 tr
inner join article3_1 art on art.idarticle = Tr.iditem
WHERE tr.ItemType = 2 AND tr.Market1 = 1
AND ((art.IDARTICLE > 0) AND ( (LCASE(art.Artikelnummer) like '%a4 papier%') OR ((LCASE(art.Artikelnummer) like 'a4')
AND (LCASE(art.Artikelnummer) like 'papier')) OR (LCASE(art.Artikelnaam1) like '%a4 papier%') OR ((LCASE(art.Artikelnaam1) like '%a4%')
AND (LCASE(art.Artikelnaam1) like '%papier%')) OR (LCASE(art.Artikelnaam2) like '%a4 papier%') OR ((LCASE(art.Artikelnaam2) like '%a4%')
AND (LCASE(art.Artikelnaam2) like '%papier%')) OR (LCASE(art.Artikelnr_leverancier) like '%a4 papier%') OR ((LCASE(art.Artikelnr_leverancier) like '%a4%')
AND (LCASE(art.Artikelnr_leverancier) like '%papier%')) OR (LCASE(art.Merk) like '%a4 papier%') OR ((LCASE(art.Merk) like '%a4%')
AND (LCASE(art.Merk) like '%papier%')) OR (LCASE(art.EAN) like '%a4 papier%') OR ((LCASE(art.EAN) like '%a4%')
AND (LCASE(art.EAN) like '%papier%')) OR (LCASE(art.AltArtnr1) like '%a4 papier%') OR ((LCASE(art.AltArtnr1) like '%a4%')
AND (LCASE(art.AltArtnr1) like '%papier%')) OR (LCASE(art.AltArtnr2) like '%a4 papier%') OR ((LCASE(art.AltArtnr2) like '%a4%')
AND (LCASE(art.AltArtnr2) like '%papier%'))))
AND tr.NODELEVEL =5 and tr.LINKTYPE <> 5
ORDER BY tr.NodePosition LIMIT 30;
================================================= ===
tôi có truy vấn thực hiện với FlameRobin:
> Prepare time: 0.016s Field #01: TREE3.IDLINK Alias:IDLINK Type:INTEGER
> Field #02: TREE3.IDTARGETLINK Alias:IDTARGETLINK Type:INTEGER Field
> #03: TREE3.IDITEM Alias:IDITEM Type:INTEGER Field #04: TREE3.NODEPOSITION Alias:NODEPOSITION Type:INTEGER PLAN SORT (SORT
> (JOIN (TR INDEX (IDX_TREE3_2, IDX_TREE3_3), ART INDEX
> (RDB$PRIMARY2))))
>
> 873424 fetches, 0 marks, 12892 reads, 0 writes. 0 inserts, 0 updates,
> 0 deletes, 380580 index, 0 seq. Delta memory: 1784 bytes. Total
> execution time: 1.311s
Cảm ơn bạn!
Tree3 là gì? Bạn đã liệt kê bảng article3_1 hai lần. – nater
Rất tiếc, tôi đã thêm hai lần cùng một siêu dữ liệu. – VanderLinde